Two dimensional motion - intitial velocity?

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Homework Help Overview

The discussion revolves around a two-dimensional motion problem involving a projectile. The original poster presents a scenario where a ball is thrown horizontally from a height of 8.0 m and lands 10.0 m away. The goal is to determine the initial velocity of the projectile.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between vertical and horizontal motion, with one suggesting the need to calculate the time the ball is in the air based on vertical motion before addressing horizontal distance and velocity.

Discussion Status

Some guidance has been offered regarding the separation of vertical and horizontal components of motion. Participants are actively discussing how to approach the problem, but there is no explicit consensus on the method or solution yet.

Contextual Notes

There is a mention of the absence of mass in the problem, which may influence the discussion on the factors affecting projectile motion.

erico004
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two dimensional motion - intitial velocity??

so i have the vertical distance, 8.0 m, and the horizantal distance, 10.0 m, how do i find the initial velocity of the projectile??
 
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I'm guessing this problem says that something was fired horizontally at an initial velocity v...blah blah, find v. Is that correct?
 
Last edited:
no :[

a student threw a ball horizontally out of a window 8.0 m above the ground. it was caught at ground level by another student who was 10.0 m away. what was the initial velocity of the ball?

no masssss
 
Ok. This is not hard. You have to break the problem up into two parts.

First, you want to find the time that the ball is in the air. To do this you only consider the vertical motion (You can do this since vertical and horizontal motion are independent of each other). So, initially there was no vertical velocity. using d=v[tex]_{i}[/tex]t + [tex]\frac{1}{2}[/tex]at[tex]^{2}[/tex] you can solve for the time.

Next, you consider the horizontal motion. Now we know the time and the horizontal distance. We also know that the horizontal velocity will stay constant. Now you can use d=v[tex]_{horiz}[/tex]t and solve for the velocity.

Hope that helps.
 

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