Two electrons, one moving towards the other.

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The discussion focuses on calculating the final speed of a moving electron as it approaches a fixed electron. The initial velocity is given as 10^5 m/s, and the distance between the electrons is 10^-8 m. The user attempts to equate work done to find the distance at which kinetic energy becomes zero, leading to confusion about the relationship between electric force and kinetic energy. It's clarified that energy and force are different concepts, and the motion of the electron won't reverse instantaneously. The conservative nature of the electric field suggests that the return path of the moving electron will mirror its approach, which could simplify the calculations.
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Homework Statement


Two electrons, one moving towards the other that is in a fixed position. Determine the final speed of the mobile electron when it is far away from the fixed one.

Initial Velocity 10^5m/s directly at the fixed electron.
Mass electron = 9 x 10^-31kg
distance between them 10^-8m


Homework Equations


W=Fd
Work initial = Work final


The Attempt at a Solution


I first attempted to find the distance r between the two electrons, when KE final is zero. I set Wfinal = Winitial and solved for r. r = 5.8 x 10^-8, which is larger than the original d= 10^-8.

The Force on q at r= 10^-8m is also much larger than the KE of the moving electron. Does Electric Field Force > KE mean that the particle should instantly reverse directions and be repelled away?

If my assumption is correct I can then find the final velocity by equating Fd = KE and solving for v. Where d = "far away" = 1m

Thanks!
 
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You'll have to show more of your work. For example, in your first attempt, how did you go about calculating the value of r?

Also, Energy is not force (different things entirely) so you can't directly compare them and draw any conclusions without knowing more about the things involved. In physics, almost nothing happens "instantly" when it comes to motion of objects with mass.

You might think about the fact that the electric field is a conservative one, so that you can expect the moving electron's return path from its "close encounter" with the fixed electron to be a mirror image of its inbound trajectory. This might save you some work, so to speak.
 
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