Two Limit exercises of functions of two variables.

Click For Summary
The discussion focuses on finding and proving the limits of functions of two variables as they approach specific points. The first limit, as (x,y) approaches (0,0), is uncertain, while the second limit, as (x,y) approaches (C,0) where C is non-zero, is believed to be (0,0) due to the absence of discontinuities. Participants emphasize the importance of establishing a positive Delta for every Epsilon to prove the limits exist. Various methods, including polar coordinates and bounding functions, have been explored, but challenges remain in establishing useful relations. Assistance is requested for proving these limits effectively.
Thomasyar
Messages
1
Reaction score
0
(I) Find the limit (x,y)->(0,0) of F, then prove it by definition.
upload_2018-2-6_18-4-16.png

(II) Find the limit and prove it by definition of:
upload_2018-2-6_18-7-29.png

as (x,y) approach (C,0), C different from zero.
I have previously asked it on Quora, but it doesn't appear to have answers any time soon, and then I've encountered this forum.
--------------------
upload_2018-2-6_18-16-43.png

As every limit, the idea is to prove that it exist a positive Delta, which delimits the values of (x,y), for every Epsilon greater than zero. The common way to do it is to find a functional expression of Epsilon as a variable of the function Delta, where the domain of that function goes from zero to infinity, (0, +inf). Now, I have tried on both exercises multiple ways of findings relations between |(x,y)| and the corresponding function, all have failed.

In the second exercise the limit is obviously (0,0), due it doesn't have any discontinuity issue. But in the first one, I'm not totally sure if the limit exists. If it does, is (0,0).

The only thing that I explored deeply is delimiting the sine function as follows:
Abs(Sin(t)) <= Abs(t), and then t=x*y, since x <= |(x,y)| (same for y), so x*y <= |(x,y)|^2
(If 0 < C1 <= C3, and 0 < C2 <= C3, then C1*C2 <= C3*C2 <= C3^2; that’s what I used)
But that only lead me to have some sort of function of x and y in the denominator, and that is not useful.
(I managed to delimit |F(x,y)|<= 1/(sqrt(1+abs(y)))

Unless having some relation of the sort |F(x,y)|<= 1/J(x,y) is useful, I think gaining a relation of |(x,y)| in the denominator does not worth the try.

I would really appreciate it if someone gives me some help on proving those limits :)
 

Attachments

  • upload_2018-2-6_18-4-16.png
    upload_2018-2-6_18-4-16.png
    2.8 KB · Views: 982
  • upload_2018-2-6_18-7-29.png
    upload_2018-2-6_18-7-29.png
    2.5 KB · Views: 933
  • upload_2018-2-6_18-16-43.png
    upload_2018-2-6_18-16-43.png
    16.8 KB · Views: 1,003
Physics news on Phys.org
Thomasyar said:
(I) Find the limit (x,y)->(0,0) of F, then prove it by definition.
View attachment 219827
(II) Find the limit and prove it by definition of:
View attachment 219828
as (x,y) approach (C,0), C different from zero.
I have previously asked it on Quora, but it doesn't appear to have answers any time soon, and then I've encountered this forum.
--------------------
View attachment 219830

As every limit, the idea is to prove that it exist a positive Delta, which delimits the values of (x,y), for every Epsilon greater than zero.
The problems ask you to first find each limit, and then prove each limit using the definition of a limit (i.e., with ##\delta## and ##\epsilon##).
For the first limit I would change to polar form so that you can evaluate the limit as r approaches 0.
Thomasyar said:
The common way to do it is to find a functional expression of Epsilon as a variable of the function Delta, where the domain of that function goes from zero to infinity, (0, +inf). Now, I have tried on both exercises multiple ways of findings relations between |(x,y)| and the corresponding function, all have failed.

In the second exercise the limit is obviously (0,0), due it doesn't have any discontinuity issue.
No, the limit is not (0, 0). The limit for each function, if it exists, will be a single number.
Thomasyar said:
But in the first one, I'm not totally sure if the limit exists. If it does, is (0,0).

The only thing that I explored deeply is delimiting the sine function as follows:
Abs(Sin(t)) <= Abs(t), and then t=x*y, since x <= |(x,y)| (same for y), so x*y <= |(x,y)|^2
(If 0 < C1 <= C3, and 0 < C2 <= C3, then C1*C2 <= C3*C2 <= C3^2; that’s what I used)
But that only lead me to have some sort of function of x and y in the denominator, and that is not useful.
(I managed to delimit |F(x,y)|<= 1/(sqrt(1+abs(y)))

Unless having some relation of the sort |F(x,y)|<= 1/J(x,y) is useful,
I don't see that this is useful.
Thomasyar said:
I think gaining a relation of |(x,y)| in the denominator does not worth the try.

I would really appreciate it if someone gives me some help on proving those limits :)
BTW, the homework template that you deleted is required here. In future posts please don't delete this template.
 
  • Like
Likes tnich
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 16 ·
Replies
16
Views
3K
Replies
26
Views
4K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K