Two-point source interference pattern

Click For Summary
SUMMARY

The discussion focuses on calculating the angles of nodal lines in a two-point source interference pattern using the formula dsinθn = (n - 0.5)λ. The user successfully calculated the first two nodal lines, obtaining angles of 13.8° and 46°, but encountered a domain error when attempting to calculate the third nodal line, indicating it exceeds 90°. The frequency provided in the problem remains unclear in its relevance to the calculations.

PREREQUISITES
  • Understanding of wave interference principles
  • Familiarity with the formula dsinθn = (n - 0.5)λ
  • Basic knowledge of trigonometric functions and their domains
  • Concept of nodal lines in wave patterns
NEXT STEPS
  • Research the significance of frequency in wave interference problems
  • Learn about the derivation and application of the dsinθn formula
  • Explore the concept of domain restrictions in trigonometric functions
  • Investigate graphical representations of interference patterns
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics and interference patterns, as well as educators seeking to clarify these concepts in a classroom setting.

benca
Messages
19
Reaction score
0
Homework Statement
A two-point source operates at a frequency of 1.0 Hz to produce an interference pattern in a ripple tank. The sources are 2.5 cm apart and the wavelength of the waves is 1.2 cm.

Calculate the angles at which the nodal lines in the pattern are located far from the sources. (Assume the angles are measured from the central line of the pattern.)
Relevant Equations
λ = (xn/L)[d/(n - 0.5)]
dsinθn= (n - 0.5)λ
xn = perpendicular distance from the right bisector t o the point Pn on the nodal line
L = distance from midpoint between the two sources to the point Pn
n = number of the nodal line
d= separation of the sources
I'm having trouble understanding what it's asking me. "Calculate the angles at which the nodal lines in the pattern are located far from the sources." I assume they are very far away, making lines PnS1 and PnC parallel. Is the question asking me to calculate θ' in the example?

"nodal lines" should I solve for several different values of n? I was thinking of using dsinθn= (n - 0.5)λ to solve for θn since θn = θ' If that's right, for how many nodal lines do I do this? Also why would they provide the frequency? Attached in a diagram from a previous example.

20191116_130741.jpg
 
Physics news on Phys.org
RippleNodes.png

Do some web research. There is a lot of useful stuff out there.
 
So I used dsinθn= (n - 0.5)λ to solve for the first two nodal lines and got 13.8° for the first and 46° for the second. When I tried to to input 3 for n I got a domain error. Does that mean the third nodal line is greater than 90° and didn't strike the screen?

I also still don't know the reason why frequency is provided.
 
Last edited:
benca said:
Does that mean the third nodal line is greater than 90° and didn't strike the screen?
What do you think? Calculate sinθ3 and see what you get.
benca said:
I also still don't know the reason why frequency is provided.
I don't know either.
 

Similar threads

Replies
11
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 12 ·
Replies
12
Views
9K
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
6K
Replies
6
Views
7K