Two questions Speed question, momentum in collisions

AI Thread Summary
The discussion focuses on two physics problems involving conservation of energy and momentum. The first problem involves a particle starting from rest at a height of 40 cm on a smooth track, where the speed at the bottom can be calculated using energy conservation principles. The second problem examines a marble colliding with a massive metallic sphere, where the marble comes to rest, and the final velocity of the sphere can be determined through momentum conservation. It is noted that kinetic energy is not lost in the collision but transformed into another form. The conversation emphasizes the importance of understanding these fundamental principles for solving the problems effectively.
dud8118
Messages
1
Reaction score
0
1.A particle starts out at rest at point A at the top of a smooth curved track of vertical height 40cm.
a> what is its speed at the bottom of the curved track? b> How far along the adjoining inclined plane, which makes an angle of 30 degree with the horizontal, will the particle go, assuming that all contacts are smooth?

2.Consider a light weight marble of mass m rolling at a speed of 20cm/s toward a very messive metallic sphere of the same size and of mass M suppose that as result of the collision the marble come to rest. a> what is the final velocity of the metallic sphere? b> Assuming the radii of the sphere are very small, calculate the kinetic energy lost by the system in this collision.

I attached the diagram which i drew poorly sorry Please help me, this is my review for the test. I have test tommorow and I tried to look for simliar problem on web and searching through the book for hint but i just can't grasp this... these are two questions i have left... that i couldn't solve it
 

Attachments

  • Physics.jpg
    Physics.jpg
    13.2 KB · Views: 437
Last edited:
Physics news on Phys.org
1. simple conservation of energy problem. You don't have friction, therefore, you are in conservative problem.

2. simple conservation of momentum problem. What happens before and after the collision should be equivalent.

Whether the size of the sphere, kinetic energy is not lost. It can be transform into another form of energy.

Cheers
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top