Two satellites in orbit around Jupiter

AI Thread Summary
Two satellites orbit Jupiter, with one having an orbital radius r and a period of 16 hours, while the second has an orbital radius of 4.0r. To find the period of the second satellite, Kepler's law indicates that the square of the period is proportional to the cube of the radius. The calculations suggest that the second satellite takes approximately 130 hours to complete one revolution, aligning closely with answer choice A. Despite some confusion in the calculations, the application of Kepler's law ultimately provides the correct method for solving the problem.
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Homework Statement



Two satellites are in circular orbits around Jupiter. One, with orbital radius r, makes one revolution every 16 h. The other satellite has orbital radius 4.0r. How long does the second satellite take to make one revolution around Jupiter?

A. 130 hours
B. 120 h
C. 140 h
D. 110 h
E. 90 h

Homework Equations



v = sqrt( GMj / r )

T = (2*pi*r) / v

G = 6.673*10^-11

Mj = 1.90*10^27

The Attempt at a Solution



I'm assuming that this is just an algebra problem at this point, but I'm having trouble finding r.

T = ( 2*pi*r) / sqrt( GMj / r )

r = [(GMjT^2) / (4pi^2)]^(1/3)

When I solve for r and then plug r back into the equation for T I do not get 16, which means I'm not doing something right here.

Do I need to convert the 16 hours / revolution into another unit before solving for r?

Any pointers?
 
Last edited:
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According to Kepler's law the square of the period varies as the cube of the orbit radius.

T^2 \propto R^3

This implies that for any given set of orbits around a common central body, that

\frac{T^2}{R^3} = Constant

You should be able to use this fact to determine the "mystery" orbital period.
 
Thanks, that did help a lot.

It seems like the method I was trying to work through would also work but is much longer.

It also doesn't help that when I do the calculation with either method I still do not get a value the exactly matches one of the answer choices, but is very close to answer A ( which did turn out to be correct ).
 
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