Two springs supporting a mass verticle

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SUMMARY

The discussion centers on the oscillation of a mass supported by two vertical springs with spring constants k1 and k2. The derived angular frequency of oscillation is expressed as √((k1+k2)/m), applicable when the springs are arranged in parallel. The analysis clarifies that gravity is not neglected; instead, it is accounted for by measuring displacement from the equilibrium position, effectively shifting the zero point without altering the oscillation dynamics.

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  • Understanding of Hooke's Law and spring constants
  • Basic knowledge of oscillatory motion and angular frequency
  • Familiarity with Newton's second law of motion (F = ma)
  • Concept of equilibrium position in mechanical systems
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  • Study the derivation of angular frequency in oscillatory systems
  • Explore the effects of damping on oscillations in spring systems
  • Learn about the differences between series and parallel spring configurations
  • Investigate the role of gravitational forces in oscillatory motion
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Homework Statement


Two springs have spring constants k1 and k2, are in a vertical position to support a single object of mass m. Show that the angular frequency of oscillation is ((k1+k2)/m)^(1/2) if the springs are in parallel.



The Attempt at a Solution




The book then goes on to explain
F = ma = -k1*x - k2*x
a + ((k1+k2)*x) / m = 0
where (k1+k2)/m = w^2
my question is why is gravity neglected?
 
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They aren't really neglecting gravity. Note that the displacement (the x) is measured from the equilibrium position, so the effect of gravity is already included. (Gravity, being a constant force, merely shifts the zero point.)
 

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