Two States of Polarization of EM Waves

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The discussion centers on the two independent states of polarization of electromagnetic waves within a metallic cavity resonator. It explains that these polarizations, often simplified as horizontal and vertical, can exist separately and carry distinct frequencies. The geometry of the cavity restricts the supported frequencies to specific narrow bands, while each polarization contributes equally to the total energy within the cavity. The need to multiply by a factor of 2 is clarified by the existence of orthogonal modes that each polarization can support. Overall, the cavity resonator's design limits polarization to two states and narrows the frequency range.
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I am studying about the cavity radiation inside a metallic cube. In the textbook it states that there are two independent waves corresponding to the two possible states of polarization of electromagnetic waves. What does it mean by this? (My current assumption is the phase change of the waves)

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It's stated in the last sentence before the equation (1-11). The textbook is "Quantum Physics of Atoms, Molecules, Solids, Nuclei, and Particles" by Eisberg R. and Resnick R. if it helps. I'm don't understand on the need to multiply by a factor of 2.
 

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If you imagine communication via a square waveguide, it is possible to use, say, either vertically polarised waves or horizontally polarised waves. These have a separate existence and we can send different messages on either one and they can also have different frequencies. If we put metal plates on either end of the square waveguide, we have a cavity resonator, and two polarisations can still exist inside it. But now, due to the geometry, only certain narrow frequency bands can be supported.
Although I said horizontal and vertical, this is a simplification, as a very large number of modes can exist, but each one has its orthogonal, or cross polarised, partner. Each polarisation contains half the total energy in the cavity.
 
tech99 said:
If you imagine communication via a square waveguide, it is possible to use, say, either vertically polarised waves or horizontally polarised waves. These have a separate existence and we can send different messages on either one and they can also have different frequencies. If we put metal plates on either end of the square waveguide, we have a cavity resonator, and two polarisations can still exist inside it. But now, due to the geometry, only certain narrow frequency bands can be supported.
Although I said horizontal and vertical, this is a simplification, as a very large number of modes can exist, but each one has its orthogonal, or cross polarised, partner. Each polarisation contains half the total energy in the cavity.

So, what I understand is that the cavity resonator limits the polarization to 2 states and also narrows the allowed frequencies. This explains so much, thanks.
 
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