Two Trains and a Bee: Distance Question

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Homework Help Overview

The problem involves two trains moving towards each other and a bee flying back and forth between them until they collide. The context is rooted in kinematics, focusing on distance, speed, and time relationships.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive the distance of the bee's first flight using equations of motion. There is uncertainty about how to formulate a general equation for the bee's subsequent flights, with questions raised about the potential use of summation or series.

Discussion Status

Participants are exploring the problem's setup and the implications of the bee's speed relative to the trains. Some guidance has been offered regarding the nature of the general equation, but there is no explicit consensus on the approach to take.

Contextual Notes

The problem assumes the bee is faster than the trains and involves a scenario where the bee reverses direction upon encountering each train. There is a reference to a similar thread, indicating potential overlap in discussion topics.

putongren
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Homework Statement
Two Trains and a Bee.
Consider two trains moving in opposite directions on the same track. The trains start simultaneouslyfrom two towns, Aville and Bville, separated by a distance d. Each train travels
toward each other with constant speed v. A bee is initially located in front of the train in
Aville. As the train departs Aville, the bee travels with speed u>v along the track towards
Bville. When it encounters the second train, it instantaneously reverses direction until it
encounters the first train, then it reverses again, etc. The bee continues flying between the
two trains until it is crushed between the trains impacting each other. The purpose of this
problem is to compute the total distance flown by the bee until it is crushed. Assume that
the bee is faster than the trains.
Relevant Equations
distance = rate * time
This is a question from the MIT Open courseware website.

(1). d = vt + ut let t = time it takes
d = (u + v)t
t = d / (u + v)
(2). d = vt + ut
d - vt = ut. Substitute t with d / (u + v)
d - v*(d/(u+v)) = u*(d/(u+v))
d - v*(d/(u+v)) = “distance of bee’s first flight"

This is to get the distance of the bee’s first flight. I’m not sure how to get the general equation for the nth flight, which is much harder. Does the general equation involve summation or series?
 
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putongren said:
Homework Statement: Two Trains and a Bee.
Consider two trains moving in opposite directions on the same track. The trains start simultaneouslyfrom two towns, Aville and Bville, separated by a distance d. Each train travels
toward each other with constant speed v. A bee is initially located in front of the train in
Aville. As the train departs Aville, the bee travels with speed u>v along the track towards
Bville. When it encounters the second train, it instantaneously reverses direction until it
encounters the first train, then it reverses again, etc. The bee continues flying between the
two trains until it is crushed between the trains impacting each other. The purpose of this
problem is to compute the total distance flown by the bee until it is crushed. Assume that
the bee is faster than the trains.
Relevant Equations: distance = rate * time

Does the general equation involve summation or series?
No, it does not.
 

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