Ugly first order differential equation

cameuth
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Homework Statement


solve the differential equation:
(1+t^2)y'+4ty=(1+t^2)^-2

Homework Equations



μ=exp∫adt

The Attempt at a Solution


this problem gets quite ugly, so here goes.
first question
does μ=e^(1+t^2)^2
 
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I don't think the integrating factor is as bad as you think.
write the equation as y'+ \frac{4ty}{1+t^2}= \frac{1}{(1+t^2)^3}
now what do I need to multiply this equation through to run the product rule backwards on the left hand side.
 
cameuth said:
μ=e^(1+t^2)^2
Nope. How did you get that?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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