Unable to solve rotation KE problem using torque

  • Thread starter Thread starter Zynoakib
  • Start date Start date
  • Tags Tags
    Rotation Torque
AI Thread Summary
The discussion revolves around a problem involving a trebuchet modeled as a stiff rod with two masses at its ends. The user successfully calculated the maximum speed of the small mass using rotational kinetic energy but struggled to achieve the same result using torque. They calculated the net torque and moment of inertia but questioned whether the non-constant torque during rotation affected their results. Other participants confirmed that torque varies throughout the motion, which complicates the calculations. Understanding the changing torque is crucial for accurately determining the angular acceleration and speed of the small mass.
Zynoakib
Messages
70
Reaction score
0

Homework Statement


A war-wolf or trebuchet is a device used during the Middle
Ages to throw rocks at castles and now sometimes
used to fling large vegetables and pianos as a sport. Model it
as a stiff rod of negligible mass, 3.00 m long, joining
particles of mass m1 = 0.120 kg and m2= 60.0 kg at its
ends. It can turn on a frictionless, horizontal axle perpendicular
to the rod and 14.0 cm from the large-mass
particle. The operator releases the trebuchet from rest
in a horizontal orientation. Find the maximum
speed that the small-mass object attains.

Homework Equations

The Attempt at a Solution


I could get the answer using rotational KE concept but when do the same thing with torque, I cannot get the answer.

Net torque = (60)(9.8)(0.14) - (0.12)(9.8)(2.86) = 78.96 Nm

Find the moment of inertia of the system

Center of mass of the system: [(0.12)(0) + (60)(3)]/ 60.12 = 2.994 m

Moment of inertia at CM
(0.12)(2.994)^2 + (60)(3 - 2.944)^2 = 1.078 kgm^2

Moment of inertia = Moment of inertia at CM + MD^2 = 1.078 + (60 + 0.12)(2.994 - 2.86)^2 = 2.158 kgm^2

Net torque = moment of inertia x angular acceleration
78.96 = 2.158 x acceleration
acceleration = 36.6 rads^-2

s = 1.57 rad, a = 36.6, u = 0, v = ?
v = 10.7 rad/s = 30.66 m/s, which is wrong

Is that because the downward force by weight is not constant during the rotation, so that the torque and the angular acceleration I calculated will become wrong as they way I calculated it seems to treat everything to be constant during the rotation

Thanks!
 
Physics news on Phys.org
No, the torque is not constant during the motion. How do you calculate the torque?
 
  • Like
Likes Zynoakib
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top