Unbelievable Rainbow Phenomenon: 4 Cycles of Color!

AI Thread Summary
A unique rainbow phenomenon was observed, featuring a magenta inner arc instead of the typical blue, with four overlapping cycles of colors. This effect is believed to result from sunlight reflecting multiple times within raindrops before refracting out, leading to interference patterns similar to thin film interference. The phenomenon is identified as "supernumerary arcs," which occur due to the interference of light waves. Participants in the discussion shared their experiences and resources for further understanding of this optical occurrence. The conversation highlights the complexity of rainbow formation and the intriguing variations that can arise under specific conditions.
Chi Meson
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Last evening there was the perfect rainbow condition: A bright evening sun shining into a rainstorm just overhead. I went outside to see both complete arcs from horizon to horizon . THen...


the inner rainbow (the most commonly seen rainbow, with red on the outside of the bow) looked odd: instead of blue on the inside, it was definitely magenta. Then I noticed that the entire cycle of colors repeated a total of four times. Each cycle overlapped the red on top of the previous blue (hence the magenta). Each cycle got fainter and tighter together so that I assumed that it continued ad infinitum but was too faint to be seen after the fourth order. I have never seen nor heard of this rainbow phenomena before. My only guess is that this is due to sunlight internally reflecting inside the raindrop for one, two, or three laps inside the drop before refracting out.

Has anyone heard of, or seen, or have an explanation of this?
 
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the rain bow originates from a process called chromatic dispersion, ie the different frequencies that make up the incident sun light (EM-wave) each are reflected under a different angle. The fact that such patterns repeat themselves is due to the interference of the reflected waves. This is just like the thin film interference on an oil-spot on the ground. Some times there will be reagons where it is dark. Light is reflected but there is destructive interference of the eflected waves. This is dependent of several facteros, the thickness of the oil-film being one of them

marlon

go check out hyperphysics http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html

chose light and vision and then atmosferic phenomena
 
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Chi Meson said:
Last evening there was the perfect rainbow condition: A bright evening sun shining into a rainstorm just overhead. I went outside to see both complete arcs from horizon to horizon . THen...

the inner rainbow (the most commonly seen rainbow, with red on the outside of the bow) looked odd: instead of blue on the inside, it was definitely magenta. Then I noticed that the entire cycle of colors repeated a total of four times. Each cycle overlapped the red on top of the previous blue (hence the magenta). Each cycle got fainter and tighter together so that I assumed that it continued ad infinitum but was too faint to be seen after the fourth order. I have never seen nor heard of this rainbow phenomena before. My only guess is that this is due to sunlight internally reflecting inside the raindrop for one, two, or three laps inside the drop before refracting out.

Has anyone heard of, or seen, or have an explanation of this?
Hey, we got that here, too - Sunday night. I'll post my pics later...
 
Great site, thanks. So, the name of these things are "supernumerary arcs." After a google search I found this explanation
http://www.sundog.clara.co.uk/rainbows/supform.htm
which is, like Marlon said, more similar to thin film interference. All sites I looked at said simple geometric/refraction explanations fail.
 
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Thread 'Gauss' law seems to imply instantaneous electric field'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Maxwell’s equations imply the following wave equation for the electric field $$\nabla^2\mathbf{E}-\frac{1}{c^2}\frac{\partial^2\mathbf{E}}{\partial t^2} = \frac{1}{\varepsilon_0}\nabla\rho+\mu_0\frac{\partial\mathbf J}{\partial t}.\tag{1}$$ I wonder if eqn.##(1)## can be split into the following transverse part $$\nabla^2\mathbf{E}_T-\frac{1}{c^2}\frac{\partial^2\mathbf{E}_T}{\partial t^2} = \mu_0\frac{\partial\mathbf{J}_T}{\partial t}\tag{2}$$ and longitudinal part...

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