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Uncertainty principle in classical mechanics boundary

  1. Jun 15, 2009 #1
    Hallo,

    Why does dp*dx>>h represents classical mechanics state?

    Thanks,
    Omri
     
  2. jcsd
  3. Jun 15, 2009 #2
    You could interpret it as taking the limit of the Planck constant [tex]h\downarrow 0[/tex]. Since quantum mechanical effects are typically of order [tex]O(h)[/tex], this limit, in some sense, puts these 'quantum corrections' to zero. This way you end up in a regime which is effectively described by classical mechanics. The corresponding physical states are classical.
     
  4. Jun 15, 2009 #3
    Thanks,

    i misunderstood you, if quantum mechanical effects are of order O(h) how does dp*dx>>h represents classical mechanics state?
     
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