Why does dp*dx>>h represents classical mechanics state?
You could interpret it as taking the limit of the Planck constant [tex]h\downarrow 0[/tex]. Since quantum mechanical effects are typically of order [tex]O(h)[/tex], this limit, in some sense, puts these 'quantum corrections' to zero. This way you end up in a regime which is effectively described by classical mechanics. The corresponding physical states are classical.
i misunderstood you, if quantum mechanical effects are of order O(h) how does dp*dx>>h represents classical mechanics state?
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