Uncertainty principle - just want to check my method

AI Thread Summary
The discussion focuses on estimating the kinetic energy of a quark confined in a proton using Heisenberg's uncertainty principle and kinetic energy equations. Participants clarify how to derive the uncertainty in momentum (Δp) from the uncertainty in position (Δx) and discuss whether it is appropriate to express the change in kinetic energy (ΔT) in terms of Δp. It is confirmed that using the relation ΔT = Δp²/(2m) is acceptable for this calculation. There is also a mention of an alternative method involving differentiation, but the consensus leans towards the simpler approach. The thread emphasizes the importance of understanding when to apply different methods in quantum mechanics calculations.
quantumlolz
Messages
7
Reaction score
0

Homework Statement



Estimate the kinetic energy of a constituent quark of mass 300 MeV/c^2 confined insdide a proton of radius 1 fm

Homework Equations



Heisenberg's uncertainty principle \Delta x \Delta p \approx \hbar (1)
Kinetic energy T=\frac{p^2}{2m} (2)

The Attempt at a Solution



So we've got \Delta x. So we can rearrange (1) to get \Delta p

Then we need to use (2). Is it OK to just say \Delta T = \frac{\Delta p^{2}}{2m}

Alternatively could we use the relation that delta T = dT/dp delta p but then we'd need to know p as well. And how would we then use this to get T?

This should be easy, but I never know when to use the second method using differentiation and when not to. Cheers.
 
Physics news on Phys.org
quantumlolz said:

Homework Statement



Estimate the kinetic energy of a constituent quark of mass 300 MeV/c^2 confined insdide a proton of radius 1 fm

The Attempt at a Solution



So we've got \Delta x. So we can rearrange (1) to get \Delta p

Then we need to use (2). Is it OK to just say \Delta T = \frac{\Delta p^{2}}{2m}

That is perfectly fine.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top