Understanding AlGaAs/GaAs Band Gap and Conduction Band Offset Variations

daffoddill
Messages
8
Reaction score
0
how the conduction band offset varies with Al concentration?? what is the different?
 
Physics news on Phys.org
This is a very vague question. If you want specific numbers you will have to read journal articles on experiments that measure conduction band offsets. If you want a qualitative answer, you know AlAs/GaAs is a type I band offset, with AlAs having the larger band gap. And when you have GaAs/GaAs, there is no offset. So as you increase Al concentration, the CBO will increase all the way to the max CBO of AlAs/GaAs. To find the exact form of the increase in the CBO you need to read journals.
 
let say for AlGaAs/GaAs/AlGaAs structure, why Al increases the conduction band offset in this case?

do you have any suggestion about the link that i can access to the journal? There's a lot of them but need to pay.
 
I just told you why Al increases the CBO. Since it increases the band gap, and you also know the initial % Al = 0 then CBO = 0 and the final % Al = 1 then CBO > 0. Therefore as you increase Al concentration you must increase the CBO.

As for the journals, I can't help you there.
 

Thread 'Initial conditions for orbits around a wormhole'

Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
View full post »

Thread 'Please tell me where I am going wrong in this integral'

##|\Psi|^2=\frac{1}{\sqrt{\pi b^2}}\exp(\frac{-(x-x_0)^2}{b^2}).## ##\braket{x}=\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dx\,x\exp(-\frac{(x-x_0)^2}{b^2}).## ##y=x-x_0 \quad x=y+x_0 \quad dy=dx.## The boundaries remain infinite, I believe. ##\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dy(y+x_0)\exp(\frac{-y^2}{b^2}).## ##\frac{2}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,y\exp(\frac{-y^2}{b^2})+\frac{2x_0}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,\exp(-\frac{y^2}{b^2}).## I then resolved the two...
View full post »

Similar threads

How Does Band Gap Influence Lattice Spacing in Materials?
Replies
1
Views
1K
Semiconductor quatum well find band gap question
Replies
1
Views
2K
I Insulator band gap and applied voltage?
Replies
2
Views
3K
Lorentzian lineshape, uncertainty principle and AlGaAs conduction band offset
Replies
3
Views
3K
I Why diode with larger band gap has larger onset potential?
Replies
7
Views
3K
A The main charge carrier in the ionic crystal is polaron or conduction?
Replies
2
Views
2K
Quick question about semiconductor alloys and band gaps?
Replies
1
Views
4K
Why is the band offset of an LED equal to the band gap?
Replies
1
Views
2K
I Are the electrons in the conduction band completely free?
Replies
11
Views
4K
Energy band gap when there is an electric field
Replies
1
Views
1K

Hot Threads

Recent Insights

Back
Top