Understanding Chain Rule: Derivatives and the Quotient Rule Explained

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juice34
Could someone explain this to me please where n=y/squareroot(4vt)

∂C/∂t=(dC/dn)(∂n/∂t)=-(1/2)(n/t)(dC/dn)

When i take the derivative of 1/t^1/2 i get -(1/2)t^(-3/2) so where does the (-3/2) go to in the final answer of -(1/2)(n/t)(dC/dn). Thank you very much!
 
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n = \frac y 2 v^{-\frac 1 2}t^{-\frac 1 2}

n_t = \frac y 2 v^{-\frac 1 2}(-\frac 1 2)t^{-\frac 3 2} = \frac y 2 v^{-\frac 1 2}t^{-\frac 1 2}(-\frac 1 2)t^{-1} = (-\frac 1 2)\frac n t
 
Thank you soooooo much!
 
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