Understanding Circular Motion: Inferences from Constant Speed and Direction

AI Thread Summary
When a car moves at a constant speed along a circular path, its velocity is not zero due to its movement. Acceleration is present because the direction of the car is continuously changing, even though its speed remains constant. Therefore, the statement that acceleration is zero is incorrect. The correct inference is that none of the provided options accurately describe the situation. Understanding that acceleration is related to changes in direction is key in circular motion.
Jacobpm64
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If a car is moving at a constant speed in a circular path, what can be inferred?
a. acceleration is 0
b. velocity is 0
c. inertia is 0
d. none of these
ok, I'm not sure on this one... i know it's not B because the car is moving, so it has a velocity that isn't 0. I don't think it is C either. So now it balls down to A and D. A is confusing because i know that acceleration takes speed and direction into account. The speed is the same so there is no acceleration, but the direction is constantly changing, so there is an acceleration. Would "acceleration is 0" be incorrect because the direction is changing constantly?
 
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Sounds like you understand the problem, yes the car has an acceleration.
 
so the answer would be "none of these"?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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