Understanding Decay and Half-Life of Uranium

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Homework Help Overview

The discussion revolves around the decay and half-life of uranium isotopes, specifically Uranium-235 and Uranium-238. Participants explore whether mass changes during decay and how half-life relates to decay rates and sample weights.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants attempt to understand the implications of half-life on decay rates and sample weights. Questions arise regarding the meaning of the atomic numbers and the definition of half-life. There is also exploration of whether the decay rate remains constant or decreases over time.

Discussion Status

The discussion has progressed with participants sharing insights and clarifying concepts. Some have offered guidance on calculating decay rates and understanding the relationship between half-life and decay frequency. Multiple interpretations of the decay process are being explored, particularly regarding the behavior of decay rates over time.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the depth of exploration. There is an emphasis on understanding rather than providing direct answers, with some participants expressing uncertainty about their reasoning.

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Homework Statement


I'm not sure if whether mass changes when atoms decay. Does emitting alpha/beta/gamma cause the atoms to lose mass? I don't know :confused:

Homework Equations


Uranium-235 has a half life of 7.35x10^5 years and uranium 238 has a half life of 4.5x10^6 years. Compare the two isotopes of uranium, given that they both have the same number of atoms.

a) Which sample would have the greater weight?
b) which sample would have the greater number of decays per second?

The Attempt at a Solution



For a) I'm not really sure but I think it would be the U-238 because it has the greater half life

For b) I'm not sure if this is right, if shorter half-life means greater decays per second. But I think it should be the U-235
 
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Hi paperdoll! :smile:

paperdoll said:
For a) I'm not really sure but I think it would be the U-238 because it has the greater half life

Do you know what the number 238 represents?


paperdoll said:
For b) I'm not sure if this is right, if shorter half-life means greater decays per second. But I think it should be the U-235

What is the definition of half-life?
 
I like Serena said:
Hi paperdoll! :smile:Do you know what the number 238 represents?
What is the definition of half-life?

Hi I like Serena, long time no see ^^ since I haven't posted here for a while :)

Yes, the number 238 represents the amount of protons and neutrons in the Uranium atomokay, half life is the time it takes for an amount of a substance to decay down to half its original value.
 
paperdoll said:
Hi I like Serena, long time no see ^^ since I haven't posted here for a while :)

Yep. I know!
Good that you remember me! :shy:


paperdoll said:
Yes, the number 238 represents the amount of protons and neutrons in the Uranium atom

Yes.
So which atom is heavier?


paperdoll said:
okay, half life is the time it takes for an amount of a substance to decay down to half its original value.

Right.
So suppose each sample has 2N atoms.
Then N atoms decay from 2N atoms in the corresponding half-time T.
How many decays is that per second?
 
I like Serena said:
Yep. I know!
Good that you remember me! :shy:

Yes.
So which atom is heavier?

Right.
So suppose each sample has 2N atoms.
Then N atoms decay from 2N atoms in the corresponding half-time T.
How many decays is that per second?

Yes, I have my final physics exams soon so I'm going through the past exam papers now :) that means more questions ahah
Oh! So the U-238 must be heavier since it has more neutrons :smile:
I'm not really sure about the decays per second. Does the decay per second stay constant throughout the entire decay process or does it slowly get smaller? :confused:
 
paperdoll said:
Oh! So the U-238 must be heavier since it has more neutrons :smile:

Yep! :wink:



paperdoll said:
I'm not really sure about the decays per second. Does the decay per second stay constant throughout the entire decay process or does it slowly get smaller? :confused:

That's what I'm trying to get you to find out. :rolleyes:

If we start with 2N atoms, then after a half-time T, N atoms have decayed.
Can't you calculate the number of decays per second from that?
 
I like Serena said:
Yep! :wink:





That's what I'm trying to get you to find out. :rolleyes:

If we start with 2N atoms, then after a half-time T, N atoms have decayed.
Can't you calculate the number of decays per second from that?

would that be N/t decays per second then? o__O
that is, provided that the "t" value is measured in seconds I think :rolleyes:
 
paperdoll said:
would that be N/t decays per second then? o__O
that is, provided that the "t" value is measured in seconds I think :rolleyes:

Yep. :)
Note that if t is not in seconds, you can simply convert it to seconds.

Now to answer your last question first - does it decrease in time or not?
 
I like Serena said:
Yep. :)
Note that if t is not in seconds, you can simply convert it to seconds.

Now to answer your last question first - does it decrease in time or not?

um...so the number of decays per second should decrease after time right? :confused: because nuclear decay is an exponential curve, so eventually there will be zero decays per second I think :smile:
 
  • #10
paperdoll said:
um...so the number of decays per second should decrease after time right? :confused: because nuclear decay is an exponential curve, so eventually there will be zero decays per second I think :smile:

Right! ;)

Let's put it this way.

If you start with 2N atoms, you've got N/T decays per second.

After a time T you'd be left with N atoms.
In the next period T, N/2 atoms would decay.
So you have (N/2)/T decays per second.
That's less, isn't it?

It is indeed a downward exponential curve.
Okay.
So if we look at the two samples, of each 2N atoms with half-times T1 and T2.
What are their respective decays per second?
And which is the greater?
 
  • #11
I like Serena said:
Right! ;)

Let's put it this way.

If you start with 2N atoms, you've got N/T decays per second.

After a time T you'd be left with N atoms.
In the next period T, N/2 atoms would decay.
So you have (N/2)/T decays per second.
That's less, isn't it?

It is indeed a downward exponential curve.
Okay.
So if we look at the two samples, of each 2N atoms with half-times T1 and T2.
What are their respective decays per second?
And which is the greater?
okay hmm, so if I let T1 be U-235= that means 7.35x10^5 years
and let T2 be U-238 = that means 4.5x10^6 years

so the rate of decay will be N/T(1 or 2)

so it is N/(7.35x10^5) and N/(4.5x10^6 years)

so the one with the greater number of decays per second will be N/(7.35x10^5) which is T1 which is U-235 :smile:

I think I get it now :biggrin: Thank you I like Serena ^^ you made things extremely clear now
 
  • #12
paperdoll said:
okay hmm, so if I let T1 be U-235= that means 7.35x10^5 years
and let T2 be U-238 = that means 4.5x10^6 years

so the rate of decay will be N/T(1 or 2)

so it is N/(7.35x10^5) and N/(4.5x10^6 years)

so the one with the greater number of decays per second will be N/(7.35x10^5) which is T1 which is U-235 :smile:

I think I get it now :biggrin: Thank you I like Serena ^^ you made things extremely clear now

You're welcome! :smile:

Actually you already had the right answer:
"I'm not sure if this is right, if shorter half-life means greater decays per second."

That was true you know, but you were not sure...
I hope you don't mind that I took you the long route. :blushing:
 
  • #13
I like Serena said:
You're welcome! :smile:

Actually you already had the right answer:
"I'm not sure if this is right, if shorter half-life means greater decays per second."

That was true you know, but you were not sure...
I hope you don't mind that I took you the long route. :blushing:

Nope, I'm very happy now that i understand the concept of decay and half life fully so if the question asks me to explain it, I can now :biggrin: Yay! Hope you have a nice day :shy:
 

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