Understanding Differentials: Deriving dε = F dot dr

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Homework Help Overview

The discussion revolves around deriving the expression dε = F dot dr from the line integral of a conservative force field F, represented as ε(r) = ∫F dot dr. Participants are exploring the relationship between integrals and differentials in the context of vector calculus.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to connect the definition of an integral to the concept of differentials, questioning how to transition from the integral form to the differential form. Some are exploring the implications of the fundamental theorem of calculus in this context.

Discussion Status

There are multiple interpretations being explored regarding the derivation of dε = F dot dr. Some participants have provided insights into the relationship between total differentials and the line integral, while others are seeking clarification on specific steps in the derivation process.

Contextual Notes

Participants are grappling with the definitions and properties of integrals and differentials, particularly in the context of vector fields and conservative forces. There is an emphasis on understanding the foundational concepts without reaching a definitive conclusion.

Syrus
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Homework Statement



The proof begins: Suppose that F is conservative. Then a scalar field ε(r) can be defined as the line integral of F from the origin to the point r. So ∫F dot dr = ε(r), where the limits of integration are from 0 to r.

The next step, however, eludes me: From the definition of an integral, it then follows that an infinitesimal change in ε is given by dε = F dot dr.




Homework Equations





The Attempt at a Solution



Usually total differentials are related to partial derivatives, tangent planes, and Taylor expansions. I'm failing to fill in the intermediate steps in deriving dε = F dot dr from ∫F dot dr = ε(r) using the "definition of integral". Any insight?
 
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Upon second thought:d/dr [∫F dot dr] = d/dr [∫F dot ndr] , where n is a unit vector in the direction of dr. So,

d/dr [∫F dot ndr] = d/dr [ε(r)]. Thus,

F dot n = d/dr [ε(r)]

and so, multiplying by dr:

dε(r) = F dot ndr = F dot dr

Is this valid?
 


Syrus said:
Upon second thought:d/dr [∫F dot dr] = d/dr [∫F dot ndr] , where n is a unit vector in the direction of dr. So,

d/dr [∫F dot ndr] = d/dr [ε(r)]. Thus,

F dot n = d/dr [ε(r)]

and so, multiplying by dr:

dε(r) = F dot ndr = F dot dr

Is this valid?

Close, but [itex]\mathbf{r}[/itex] is a vector, and so an infinitesimal change in [itex]\epsilon ( \mathbf{r} )[/itex] is really

[tex]d\epsilon = \frac{ \partial \epsilon}{ \partial x} dx + \frac{ \partial \epsilon}{ \partial y} dy + \frac{ \partial \epsilon}{ \partial z} dz = \mathbf{ \nabla } \epsilon \cdot d\mathbf{r}[/tex]
 


Hi gabbagabbahey! I understand that what you posted is the equation for the total differential, I am just struggling to understand how from ∫F dot dr = ε(r) (where the limits of integration are from 0 to r) one deduces the result- in particular, using the "definition of integral".

That is, how can we derive dε = F dot dr from what we have above?
 


Syrus said:
Hi gabbagabbahey! I understand that what you posted is the equation for the total differential, I am just struggling to understand how from ∫F dot dr = ε(r) (where the limits of integration are from 0 to r) one deduces the result- in particular, using the "definition of integral".

Well, to me, the statement "From the definition of an integral" means using the fundamental theorem of calculus (FTC). For a simple one-dimensional integral, FTC tells you that if [itex]F(b)-F(a) = \int_a^b f(x) dx[/itex], then [itex]F'(x)=f(x)[/itex] (or [itex]dF = f(x)dx[/itex]).

For line integrals, this generalizes to the statement that if [itex]F(\mathbf{b}) - F(\mathbf{a}) = \int_{ \mathbf{a} }^{ \mathbf{b} } \mathbf{f} ( \mathbf{r} ) \cdot d \mathbf{r}[/itex] regardless of which path you choose for the integration, then [itex]\mathbf{\nabla} F = \mathbf{f} ( \mathbf{r} )[/itex] (or, equivalently [itex]dF=\mathbf{f} ( \mathbf{r} ) \cdot d \mathbf{r}[/itex])
 

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