Understanding Direction of Unit Vectors r roof & phi roof

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Homework Help Overview

The discussion revolves around understanding the directions of the unit vectors \(\hat{r}\) and \(\hat{\phi}\) in polar coordinates, particularly how they relate to the position vector \(\vec{r}\) as it changes. Participants are exploring the mathematical implications of differentiating the position vector with respect to the angle \(\phi\) and the geometric interpretations of these vectors.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the differentiation of the position vector \(\vec{r}\) to find the direction of \(\partial \vec{r} / \partial \phi\) and question how to interpret the resulting vector. There are inquiries about the orthogonality of the vectors and the implications of the dot product in this context.

Discussion Status

The conversation is ongoing, with participants sharing their thoughts on the mathematical expressions and questioning the geometric interpretations. Some have suggested using the dot product to explore orthogonality, while others are seeking clarification on the relationships between the vectors involved.

Contextual Notes

Participants note potential confusion regarding the notation of angles, specifically distinguishing between \(\phi\) and \(\theta\). There is also mention of a lack of visual aids or tutorials that could help clarify the geometric aspects of the discussion.

Istiak
Messages
158
Reaction score
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Homework Statement
Why angle direction is perpendicular?
Relevant Equations
vector
Screenshot from 2021-08-21 00-50-39.png

The unit vector r roof points in the direction of
increasing r with phi fixed; phi roof points in the direction of increasing phi
with r fixed. Unlike x roof, the vectors r roof and phi roof change as the position
vector r moves.
What I was thinking of the image is
Screenshot from 2021-08-21 01-15-23.png


Although, I was thinking why phi roof is perpendicular.
Screenshot from 2021-08-21 01-17-29.png
I was trying to understand that direction by the vector direction. I can't figure out that direction. Usually, I didn't do any vector of angle. I was wondering I didn't find any tutorial of angle direction in YT.
 
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What's the question exactly?
 
Start with ##\vec r = r(\cos \phi\,\hat i + \sin\phi\,\hat j)## and find the direction of ##\partial \vec r / \partial \phi##.
 
vela said:
Start with ##\vec r = r(\cos \phi\,\hat i + \sin\phi\,\hat j)## and find the direction of ##\partial \vec r / \partial \phi##.
If I differentiate that then, I get

$$\frac{\partial \vec r }{\partial \phi}=r (\cos \phi \hat j - \sin \phi \hat i)$$

But, I was thinking what I should do with the equation. 🤔
 
Istiakshovon said:
If I differentiate that then, I get

$$\frac{\partial \vec r }{\partial \phi}=r (\cos \phi \hat j - \sin \phi \hat i)$$

But, I was thinking what I should do with the equation. 🤔
What happens if you take the dot product of that with ##\hat r##?
 
Istiakshovon said:
If I differentiate that then, I get

$$\frac{\partial \vec r }{\partial \phi}=r (\cos \phi \hat j - \sin \phi \hat i)$$

But, I was thinking what I should do with the equation. 🤔
Show that vector is orthogonal to ##\vec r##
 
haruspex said:
What happens if you take the dot product of that with ##\hat r##?
$$\hat r \cdot \frac{\partial \vec r }{\partial \phi} = \hat r \frac{\partial \vec r }{\partial \phi} \cos \theta$$
$$=\hat r r (\cos \phi \hat j - \sin \phi \hat i) \cos \theta$$
 
  • Wow
Likes   Reactions: PeroK
PeroK said:
Show that vector is orthogonal to ##\vec r##
How? :thinking Did you mean to graph?
 
Istiakshovon said:
How? :thinking Did you mean to graph?
You could use the dot product - correctly, of course.
 
  • #10
Istiakshovon said:
$$\hat r \cdot \frac{\partial \vec r }{\partial \phi} = \hat r \frac{\partial \vec r }{\partial \phi} \cos \theta$$
$$=\hat r r (\cos \phi \hat j - \sin \phi \hat i) \cos \theta$$
That's an original approach to say the least!
 
  • #11
PeroK said:
You could use the dot product - correctly, of course.
To me $$\hat r r$$ represents the direction of phi is toward r. But, I think $$(\cos \phi \hat j - \sin \phi \hat i) \cos \theta$$ this are representing direction of phi is perpendicular. But, I am saying that by looking at original picture. Without that, I can't say that. So, how can I see that that's really perpendicular. 🤔
 
  • #12
Istiakshovon said:
To me $$\hat r r$$ represents the direction of phi is toward r. But, I think $$(\cos \phi \hat j - \sin \phi \hat i) \cos \theta$$ this are representing direction of phi is perpendicular. But, I am saying that by looking at original picture. Without that, I can't say that. So, how can I see that that's really perpendicular. 🤔
Note that it's either ##\phi## or ##\theta##, not both. Also, look up the dot product in Cartesian coordinates and note that:

vela said:
Start with ##\vec r = r(\cos \phi\,\hat i + \sin\phi\,\hat j)##
And
Istiakshovon said:
$$\frac{\partial \vec r }{\partial \phi}=r (\cos \phi \hat j - \sin \phi \hat i)$$
 

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