Understanding Direction of Unit Vectors r roof & phi roof

AI Thread Summary
The discussion focuses on the definitions and properties of the unit vectors r hat and phi hat in polar coordinates. The unit vector r hat indicates the direction of increasing r while keeping phi constant, whereas phi hat indicates the direction of increasing phi with r fixed. Participants explore the differentiation of the position vector r with respect to phi, leading to the expression for the change in direction. The conversation also delves into the orthogonality of the resulting vector and its relationship to the original position vector, emphasizing the use of the dot product to demonstrate this property. Overall, the discussion seeks to clarify the geometric interpretation of these vectors and their interactions.
Istiak
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Homework Statement
Why angle direction is perpendicular?
Relevant Equations
vector
Screenshot from 2021-08-21 00-50-39.png

The unit vector r roof points in the direction of
increasing r with phi fixed; phi roof points in the direction of increasing phi
with r fixed. Unlike x roof, the vectors r roof and phi roof change as the position
vector r moves.
What I was thinking of the image is
Screenshot from 2021-08-21 01-15-23.png


Although, I was thinking why phi roof is perpendicular.
Screenshot from 2021-08-21 01-17-29.png
I was trying to understand that direction by the vector direction. I can't figure out that direction. Usually, I didn't do any vector of angle. I was wondering I didn't find any tutorial of angle direction in YT.
 
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What's the question exactly?
 
Start with ##\vec r = r(\cos \phi\,\hat i + \sin\phi\,\hat j)## and find the direction of ##\partial \vec r / \partial \phi##.
 
vela said:
Start with ##\vec r = r(\cos \phi\,\hat i + \sin\phi\,\hat j)## and find the direction of ##\partial \vec r / \partial \phi##.
If I differentiate that then, I get

$$\frac{\partial \vec r }{\partial \phi}=r (\cos \phi \hat j - \sin \phi \hat i)$$

But, I was thinking what I should do with the equation. 🤔
 
Istiakshovon said:
If I differentiate that then, I get

$$\frac{\partial \vec r }{\partial \phi}=r (\cos \phi \hat j - \sin \phi \hat i)$$

But, I was thinking what I should do with the equation. 🤔
What happens if you take the dot product of that with ##\hat r##?
 
Istiakshovon said:
If I differentiate that then, I get

$$\frac{\partial \vec r }{\partial \phi}=r (\cos \phi \hat j - \sin \phi \hat i)$$

But, I was thinking what I should do with the equation. 🤔
Show that vector is orthogonal to ##\vec r##
 
haruspex said:
What happens if you take the dot product of that with ##\hat r##?
$$\hat r \cdot \frac{\partial \vec r }{\partial \phi} = \hat r \frac{\partial \vec r }{\partial \phi} \cos \theta$$
$$=\hat r r (\cos \phi \hat j - \sin \phi \hat i) \cos \theta$$
 
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PeroK said:
Show that vector is orthogonal to ##\vec r##
How? :thinking Did you mean to graph?
 
Istiakshovon said:
How? :thinking Did you mean to graph?
You could use the dot product - correctly, of course.
 
  • #10
Istiakshovon said:
$$\hat r \cdot \frac{\partial \vec r }{\partial \phi} = \hat r \frac{\partial \vec r }{\partial \phi} \cos \theta$$
$$=\hat r r (\cos \phi \hat j - \sin \phi \hat i) \cos \theta$$
That's an original approach to say the least!
 
  • #11
PeroK said:
You could use the dot product - correctly, of course.
To me $$\hat r r$$ represents the direction of phi is toward r. But, I think $$(\cos \phi \hat j - \sin \phi \hat i) \cos \theta$$ this are representing direction of phi is perpendicular. But, I am saying that by looking at original picture. Without that, I can't say that. So, how can I see that that's really perpendicular. 🤔
 
  • #12
Istiakshovon said:
To me $$\hat r r$$ represents the direction of phi is toward r. But, I think $$(\cos \phi \hat j - \sin \phi \hat i) \cos \theta$$ this are representing direction of phi is perpendicular. But, I am saying that by looking at original picture. Without that, I can't say that. So, how can I see that that's really perpendicular. 🤔
Note that it's either ##\phi## or ##\theta##, not both. Also, look up the dot product in Cartesian coordinates and note that:

vela said:
Start with ##\vec r = r(\cos \phi\,\hat i + \sin\phi\,\hat j)##
And
Istiakshovon said:
$$\frac{\partial \vec r }{\partial \phi}=r (\cos \phi \hat j - \sin \phi \hat i)$$
 
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