Engineering Understanding First Order Circuits: DC vs. AC

AI Thread Summary
The discussion revolves around the confusion regarding the behavior of an inductor in a parallel circuit with resistors in a DC context. It is clarified that even though the inductor may act as a short circuit in steady-state DC, it still allows current to flow through the resistors due to the presence of voltage across them. The voltage Vo(t) = 2V indicates that current is indeed flowing through the resistor branch, confirming that the inductor is not shorting it out. The application of Kirchhoff's Current Law (KCL) suggests that some current must be flowing through the inductor as well. Overall, the inductor's charging behavior is essential to understanding the circuit dynamics.
edsys89
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Hi, I'm confused with the solution given for this practice problem.
All of these components are said to be in parallel, yet the current is worked out only across the resistors. I thought the inductor would be a short circuit to DC.
Am I looking at this backwards, is it modelling the inductor charging up?
 

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edsys89 said:
Hi, I'm confused with the solution given for this practice problem.
All of these components are said to be in parallel, yet the current is worked out only across the resistors. I thought the inductor would be a short circuit to DC.
Am I looking at this backwards, is it modelling the inductor charging up?

The sole fact that are you given Vo(t) = 2V implies that there must be current running through the other branch of resistance because there is voltage across it. (They are in parallel) Since this current isn't identical to the current in the other resistor branch, by KCL some of it must be flowing through the inductor.

This is enough to conclude that it's not being shorted out by the inductor.
 
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