Understanding Flux of Vector Fields: Equations, Solutions, and Common Mistakes

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yecko
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Homework Statement



Example 2:[/B]
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Homework Equations


Flux=integrate -Pgx-Qgy+R of the proj. area on xy plane for z=g(x,y)

The Attempt at a Solution


Why do my attempt is wrong? The example is using the foundational formula while I use the stock formula from the book, why is there a negative sign difference between the answers? Or is that my formula used inappropiately?

Thanks![/B]
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One reason PF discourages the use of images is that they are difficult to edit. On your first line you have the equation ##g = y = x^2##, whatever that means. You are likely using the formula for a surface of the form ##z = g(x,y)##. The surface ##y = x^2## is not that kind of surface because ##y## and ##x## are not independent. The easiest way to represent the surface is ##y = g(x,z)##. In any case, however you did it, your normal vector is in the wrong direction. The ##y## component of your normal vector must be negative.
 
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LCKurtz said:
The y coordinate of your normal vector must be negative.
Thanks for pointing out the problem...
yecko said:
Flux=integrate -Pgx-Qgy+R of the proj. area on xy plane for z=g(x,y)
but how can we see the direction of normal vector in this formula?
and how to correct it? (simply by adding a negative sign?)
 
yecko said:
Thanks for pointing out the problem...

but how can we see the direction of normal vector in this formula?
and how to correct it? (simply by adding a negative sign?)

I can't tell how you got your normal or what formula you used because you didn't show your work. What I would do is parameterize the surface like this$$
\vec R(x,z) = \langle x, x^2, z\rangle$$and get a normal by ##\vec R_x\times \vec R_z## and take it or its opposite, whichever has a negative ##y## component.
 
Alright! I believe I've got it! thanks!
 
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