- #1
Saterial
- 54
- 0
Hello.
I'm just trying to understanding something here. I was taught integration by parts by my professor in what looks to be like an untraditional way.
From my understanding, the theorem states:
∫udv = uv - ∫vdu
We were given an example in class of:
∫exsin(x)dx
=∫ex∫sin(x)dx - ∫[(ex)'∫sin(x)dx]dx
=-excos(x) + ∫excos(x)dx
I don't understand how this is the same thing as if I were to use, ex as u and sin(x) as v, since the outcome would then be:
∫exsin(x)dx
=exsin(x)dx - ∫exsin(x)dx
Any help understanding this professors method would be great, thanks!
I'm just trying to understanding something here. I was taught integration by parts by my professor in what looks to be like an untraditional way.
From my understanding, the theorem states:
∫udv = uv - ∫vdu
We were given an example in class of:
∫exsin(x)dx
=∫ex∫sin(x)dx - ∫[(ex)'∫sin(x)dx]dx
=-excos(x) + ∫excos(x)dx
I don't understand how this is the same thing as if I were to use, ex as u and sin(x) as v, since the outcome would then be:
∫exsin(x)dx
=exsin(x)dx - ∫exsin(x)dx
Any help understanding this professors method would be great, thanks!