Understanding KVL and Voltage Differences

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The discussion revolves around the application of Kirchhoff's Voltage Law (KVL) in solving for voltage differences in a circuit. The initial calculation for Vx using KVL resulted in -3, while the professor's posted answer was -9, leading to confusion. Participants suggested using node analysis as an alternative method, which confirmed the initial calculation of Vx as -3. Ultimately, it was revealed that the professor's answer was a typo, validating the correct solution. The thread emphasizes the importance of verifying calculations and understanding different analysis methods in circuit problems.
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Homework Statement


eceKVL.jpg

Homework Equations


KVL, the sum of all voltages around a loop equal 0

The Attempt at a Solution


eceKVLsol.jpg


Vx is just the difference of the bottom node to the right node. With KVL I just add up the the voltage differences in a loop and equal to zero right? -15+12+6+Vx=0 Vx = -3 ... However my professor posted the answer and Vx = -9 ... why is that? what am I doing wrong?
 
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Not sure I never use KCL/KVL anymore lol.

If you know how to use node analysis you can get the answer more quickly and easily.

Establish a node as ground and the voltage at the node you want to solve you just sum the currents into that node to zero.

Establishing the right node as ground:

node analysis equation:

(3-Vx)/3 - 2 = 0

Which solves for Vx = -3

I actually ended up with the same answer as you, perhaps you should ask your professor if it's a typo?

I could've solved it incorrectly as well though.
 
Your solution is correct. Your professor made a mistake.
 
thanks for the help! i just got an email and it was a typo and the answer is -3
 

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