Understanding KVL Loop in BJT Biasing and Calculating Ve

[karandeepdps]

Please help how Ve is calculated what i think is that it should be:
-Ve=-Vee+IeRe;
How Ve is taken positive please someone draw equivalent circuit for same

 

[NascentOxygen]

V_E is defined as the emitter voltage wrt ground. Nothing about this says that V_E must turn out to be a positive voltage, though. You can see that V_E will be somewhere between -V_EE and +V_CC.

If NPN emitter current is the current out of the transistor emitter, then the upper end of R_E is the more positive. Draw arrows to show current direction, and voltage drop across resistances, and apply Kirchoff's Voltage Law.

 

[karandeepdps]

Thanks will you please help me in this question also i am confused in Vcc equations

 

[NascentOxygen]

Explain which line in the solution you are having trouble with.

 

[karandeepdps]

Last line,how they have applied kvl to an open loop.

 

[NascentOxygen]

Last line,how they have applied kvl to an open loop.

There is no open loop.

R_B is supplying base current from the positive rail, V_CC. Because the transistor is operating in the active region, its base is forward biased and its B-E potential is labelled V_BE.

The wire from the base ending in mid-air simply indicates where the amplifier's AC input will be impressed when the circuit is later completed to function as an audio amplifier, for example.