phalanx123
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two conflicting answers?
I was doing a question on differentiate parametric equations which has this result \frac{dy}{dx}=\frac{4sin(4\theta)}{sin\theta}. it then asks what the value of \frac{dy}{dx}would be if \theta=0. if I substitute \theta=0 into \frac{4sin(4\theta)}{sin\theta} than I get \frac{0}{0} which I persume would be infinity, i.e. the grdient of the graph at that point is undefinined. but if I transform \frac{4sin(4\theta)}{sin\theta} into 16cos\theta cos(4\theta) and substitute\theta=0 in than I got 16 which is the correct answer. How can this be possible?
I was doing a question on differentiate parametric equations which has this result \frac{dy}{dx}=\frac{4sin(4\theta)}{sin\theta}. it then asks what the value of \frac{dy}{dx}would be if \theta=0. if I substitute \theta=0 into \frac{4sin(4\theta)}{sin\theta} than I get \frac{0}{0} which I persume would be infinity, i.e. the grdient of the graph at that point is undefinined. but if I transform \frac{4sin(4\theta)}{sin\theta} into 16cos\theta cos(4\theta) and substitute\theta=0 in than I got 16 which is the correct answer. How can this be possible?

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