Understanding Quantum State Preparation: The Significance of |u> and |d> Vectors

Quarlep
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"Let’s begin by labeling the possible spin states along the three coordinate axes. If A is oriented along the z axis, the two possible states that can be prepared correspond to σz= ±1. Let’s call them up and down and denote them by ket-vectors |u> and |d> . Thus, when the apparatus is oriented along the z axis and registers +1, the state |u> has been prepared. " says in The Theoritical Minimum

what it means ? In particular "the state |u> has been prepared" Actually I am asking just this part
 
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It means that the system is in state |u>,
$$
| \psi \rangle = | \mathrm{u} \rangle
$$
 
By saying that the state |u\rangle is prepared, one can assume that all subsequent measurements of that same system will be as though the system is in state |u\rangle.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
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