Understanding Semidirect Products: Homomorphisms and Group Structures Explained

  • Thread starter Thread starter murmillo
  • Start date Start date
  • Tags Tags
    Product
murmillo
Messages
114
Reaction score
0
1. Homework Statement [/b]
I'm reading about semidirect products, and I don't understand this part:
Given two abstract groups H and K and a homomorphism
f : K --> AutH, define a group structure on the Cartesian product H X K
by the rule
(h1, k1) * (h2; k2) = (h1 x f(k1)(h2), k1k2).
I don't understand how how h1 x f(k1)(h2) is an element of H.


3. The Attempt at a Solution [/b]
I think that h1 x f(k1)(h2) is an element of H only when H is normal. But the rule is supposed to work for any two groups H and K.
 
Physics news on Phys.org
h1 is an element of H.
f(k1) is an automorphism of H, thus it takes elements of H to elements of H. In particular f(k1)(h2) is an element of H.
Multiplying the two element gives an element of H.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top