Understanding the Conservation of Momentum in a Hard Mud Ball Collision

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In a collision involving a hard sticky mud ball thrown at a wall, the collision is classified as inelastic, meaning kinetic energy is not conserved. While the initial momentum of the mud ball is significant, the wall's momentum is negligible due to its massive attachment to the Earth. The final momentum of the mud wall combination does have a small velocity, but the overall momentum is conserved when considering the entire Earth system. The mud will likely share a final velocity with the wall and Earth, although this change is imperceptible due to Earth's massive size. Understanding these dynamics clarifies how momentum conservation applies in this scenario.
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if a hard sticky mud ball is trown on a wall it sticks to it
it is an inelastic collision
K.E. is not conserved
but here momentum is also not conserved because mud had an initial velocity
so initial momentum of mud + initial momentum of wall (that is 0) = initial momentum of mud
final momentum of mud (that is 0 or less than its initial momentum)+final momentum of wall= 0 or less than total initial momentum
please explain hiw momentum is conserved here??
 
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The wall/mud combination does have a small final velocity. If the wall is attached to a planet, this velocity is tiny, since the mass is huge.
 
Momentum is conserved - but if the wall is attached to the ground, you have to consider the momentum of the whole earth, which changes at the impact. The mass of Earth is huge, so you won't be able to measure it.

Edit: Too slow :(
 
will the stiky mud also have a final velocity??
 
The same as the wall and earth, probably.
 
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