Understanding the Phase Constant in y(x,t) Equation

  • Context: Undergrad 
  • Thread starter Thread starter Sciencer
  • Start date Start date
  • Tags Tags
    Constant Phase
Click For Summary
SUMMARY

The discussion centers on the phase constant (PHI) in the wave equation y(x,t) = ym * sin(kx - wt - PHI). Participants clarify that PHI shifts the wave's position in space or time, impacting its behavior at specific points. A key insight is that while y(x,t) = ym * sin(-PHI) does not appear to move the wave, the phase constant is essential for accurately modeling scenarios where the wave does not start at zero. Sketching wave snapshots at different phase values (e.g., PHI = 0 and PHI = π/2) illustrates the effect of the phase shift.

PREREQUISITES
  • Understanding of wave equations and sinusoidal functions
  • Familiarity with the concepts of wave frequency (w) and wave number (k)
  • Basic knowledge of trigonometric functions and their graphs
  • Experience with mathematical modeling of physical phenomena
NEXT STEPS
  • Study the implications of phase shifts in wave mechanics
  • Explore the derivation and applications of the wave equation in different contexts
  • Learn about the significance of initial conditions in wave equations
  • Investigate graphical representations of sinusoidal functions with varying phase constants
USEFUL FOR

Students and professionals in physics, particularly those studying wave mechanics, as well as educators seeking to clarify the concept of phase constants in wave equations.

Sciencer
Messages
8
Reaction score
0
Hi,

In the equation
y(x,t) = ym * sin(kx - wt - PHI)

I thought I understand why we have that phase constant atleast mathmetically but after thinking about it I don't think I understand it completely like here in my book it says the phase constant moves the wave forward or backward in space or time. Now let's say
we have wave at t = 0 and x = 0;

we would have y(x,t) = ym * sin(-PHI) that wouldn't really move it forward or backward in space or time if we had y(x,t) = ym + PHI then yeh it would have but I don't see how it would moves it backward or forward in that case ?

I can see how they derived
y(x,t) = ym * sin(kx - wt) but that PHI keeps confusing me.
 
Physics news on Phys.org
You might try sketching a 'snapshot' of the wave (that is a graph of y against x) at t = 0, first for the case \phi = 0, then for the case \phi = \pi/2. The shift (in the x direction) of the wave profile brought about by \phi should then be clear.

The purpose of including \phi is so we have an equation which fits the general case: when y doesn't happen to be zero when x = 0 and t = 0. [An alternative, sometimes permissible, sometimes not, is to choose our zero of time (or of x) expressly to ensure that y = 0 and \frac{\partial y}{\partial x} > 0 when t = 0 and x = 0. Then we don't have to bother with \phi.]
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 3 ·
Replies
3
Views
674
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K