Understanding the Relationship between Hamilton and Momentum Operators

[dream_chaser]

why i\hbar(\partial/\partialt+i\Omega)=i\hbarexp(-i\Omegat)\partial/\partialtexp(i\Omegat)

 

[dextercioby]

In the RHS you have something that resembles the unitary trasformation of an operator. Where did you get the equation from ?

 

[K.J.Healey]

i\hbar(\frac{d}{dt}+ i\Omega) = i\hbar(exp(-i \Omega t) \frac{d}{dt} exp(i \Omega t)

Well if exp(iOt) is your wavefunction, the RHS is just i\hbar(i \Omega )

are you sure this equation is right? Looks like momentum operator, not hamilton.