Well, the (Riemann) integral from a to b is defined as the upper limit of \sum_{\bigcup \Delta x = [a, b]}f(x)\cdot\Delta x. So, if you put a=x and b=x+Δx, you get the first element in the sum. Which means that \int_{x}^{x+\Delta x}f(x)dx is the upper limit of f(x)\cdot \Delta x (as Δx→0).Muthumanimaran said:How the R.H.S of the equation (after rearranging and dividing by Λx) becomes f(x)Λx?