Understanding the Right Hand Rule: Determining Direction Using Cross-Products

AI Thread Summary
In the discussion about the right-hand rule and cross-products, the main question is determining the direction of x when z is east and y is north. The conclusion drawn is that x must be "down," as the options provided do not include "up." The reasoning involves aligning fingers according to the right-hand rule, leading to the necessity of rotating the hand to achieve the correct orientation. The user acknowledges that the absence of "up" among the choices simplifies the answer to "down." The conversation emphasizes the importance of understanding vector orientation in cross-product calculations.
Tiven white
Messages
58
Reaction score
0

Homework Statement



If z is east and y is north then x is?
A. West
B. East
C. North
D. South
E. Down

Homework Equations


I have trued getting the proper orientation but the direction I would have obtained is not an option 'up' a comment would be appreciated


The Attempt at a Solution

 
Physics news on Phys.org
Obviously, it can be either up or down. Assuming one of the given answers must be correct, that must be "down".

To see that, you would need to twist your arm quite severely. Align your middle finger (Z) with East and your index finger with South. Then your thumb will be Up. Now to make your index index finger point North as described, you would need to rotate your hand about your middle finger.
 
You did not define the equation for the cross-product vector x.

If x = y x z then x is down.
If x = z x y then x is up.

EDIT: OK, never mind, you did not have "up" as one of your choices. So voko answered the question.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top