Understanding the Use of Magnetic Field in MIT Problem 4 31-9

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The discussion centers on understanding the application of the magnetic field in MIT Problem 4 31-9, specifically regarding the variables used in the calculations. Participants clarify that the magnetic field (B) is expressed in terms of distance from the current-carrying wire, denoted as h, and the loop's dimensions, w and L. There is confusion about the integration of the magnetic field over the loop area, as the initial approach incorrectly assumes a constant distance for B. The correct method involves recognizing that B varies with distance from the wire, necessitating integration to accurately calculate magnetic flux. Overall, the key takeaway is the importance of understanding the geometry and variables involved in the problem.
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what is h?

can you tell me via some image?
 


They are integrating the B field over the area inside the loop. (Since I don't have the figure, I must go by the mathematics in their solution.) The loop must be distance, h, from the current carrying wire. The loop extends a distance, w, in the x direction and a distance L in the y direction.
 
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Hm you are right, let me get the picture.
 


What do you mean "x direction"?

When I first did it I did this

\Phi = B \cdot A = \frac{\mu_0 I}{2\pi (h + w)} \cdot Lw
 


flyingpig said:
What do you mean "x direction"?

When I first did it I did this

\Phi = B \cdot A = \frac{\mu_0 I}{2\pi (h + w)} \cdot Lw

The magnetic field you used only applies at the very bottom of the loop. In general, B is given by mu_0*I/(2*pi*r), where r is the distance from the wire. You have to integrate over the area of the loop to get the flux.
 
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