Understanding Thin Lens Formula: Image Location & Projection

[luysion]

Hi, in questions involving lenses, when using the "thin lens formulae"
if my di is negative doesn't that mean the image is on the other side of the lens?
in this example however it doesn't seem this holds true..


A doctor examines a patient's skin lesion with a 15 cm focal length magnifying glass. If this lens is held 13.5 cm from the lesion, where is the image and could it be projected onto a screen?

the answer is;
1.35 m on the patient's side of the lens and could not be projected onto a screen.

I get how to get 1.35 but i get -1.35 so shouldn't it mean that it would be on the doctors side?

can someone please explain this to me.

Cheers!

 

[tiny-tim]

A doctor examines a patient's skin lesion with a 15 cm focal length magnifying glass. If this lens is held 13.5 cm from the lesion, where is the image and could it be projected onto a screen?
…
I get how to get 1.35 but i get -1.35 so shouldn't it mean that it would be on the doctors side?

Hi luysion!

Distance is positive for real objects and images, and negative for virtual ones.

The light is coming from the patient …

if it was focussing onto a real image, it would be on the doctor's side of the lens (where you could put a screen) …

since it's on the patient's side, it's virtual and negative, which is why you get -1.35.