Understanding Trig Function Questions in the Range of Pi to 2Pi

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The discussion focuses on solving a trigonometric function problem involving the secant function in the range of π to 2π. The specific equation provided is sec A = 1.2048, which leads to the need to express it in terms of cosine. Participants note that while the secant function has two solutions in the range from 0 to 2π, only one solution exists between π and 2π. The importance of converting the secant equation to a cosine function and using the arccos function is emphasized, as it is only defined from 0 to π. Overall, the conversation highlights the challenges of interpreting trigonometric questions within specified ranges.
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Im having some problems with some trig function question...im not really understanding what they are asking with these type of questions?

help please

determine the larger angle a in the range pie<a<2pie

sec A = 1.2048

answer a= (in radians)

the answer is 5.6915 rads
 
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ok so the question is that we want to determine the larger angle \alpha in the range \pi &lt; \alpha &lt; 2\pi

Now \sec x = \frac{1}{\cos x} See if you can go from here.
 
First, start off by writing secant as a cosine function:

\frac{1}{\cos A}=1.2048

Now, solve the function for A. Remember, \arccos A is only defined from 0 to \pi so you have to find a corresponding angle between \pi and 2\pi

good luck.
 
yea but how do i put it in radians?
 
This question would make more sense if asked about the range from 0 to 2\pi, since there would be two angles with sec = 1.2048. But there's only one in the range of \pi to 2\pi, so the question doesn't make that much sense.
 
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