Understanding Uniform Circular Motion: The Role of Perpendicular Acceleration

  • Thread starter Thread starter KD
  • Start date Start date
  • Tags Tags
    Concept
AI Thread Summary
Forces that are perpendicular to each other are independent, which is crucial in understanding uniform circular motion. When acceleration is constant in magnitude and perpendicular to velocity, it results in a circular path without changes in speed, indicating no tangential acceleration. The centripetal acceleration acts towards the center of the circular path, maintaining the direction of motion while the speed remains constant. This relationship allows for effective vector manipulation in calculations involving forces and motion. Therefore, the concept of perpendicularity is essential for defining the nature of the motion and the forces involved.
KD
Messages
27
Reaction score
0
What does it really mean when forces are perpendicular to each other? Is it that they are independent of each other?
And if so, why is that so special?
I ask these questions to answer this homework question: Describe the path of a moving body whose acceleration is constant in magnitude at all times and is perpendicular to the velocity.
It is in the topic of tangential and centripetal accleration. Please give some helpful hints. Thanks.
 
Physics news on Phys.org
Velocity is a vector unit. If the acceleration acts perpendicular to the velocity, the moving body should be moving with circular motion.
 
We like to be able to break vectors down into components that are perpendicular to each other so that we can manipulate them, i.e. add or subtract other vectors and conduct other calculations concerning the problem. For instance, to find the centripetal force, we need to know the direction to the radius of the curve, or normal direction to correctly do calculations. This let's the other component, tangential, be along the path of motion.

In your question, the body never speeds up or slows down. So you have to know that there is no acceleration tangentially. All the acceleration is in the normal direction. What path would this create?
 
Uniform circular motion occurs when an acceleration of constant magnitude is perpendicular to tangential velocity.

Okay, so to just think through this, tangential velocity would be with changing speeds, in a straight line? And centripetal - center seeking- always circular.
Tangential -speed Centripetal - direction.
Constant in magnitude so there is no change in speed so there is no tangential acceleration. So you can only assume that it is going with the other component of acceleration - centripetal. So it has to go in a circular path. With that being said, why is "perpendicular to the velocity" even essential to the question?
Thanks for your help!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top