- #1
simon96c
- 11
- 0
Hello everyone,
I am currently studying traveling waves and reflection but I didn't understand a part of my last lesson.
If we consider a string with a loose end and the other end attached to a wall we expect the string to have zero displacement at the wall and to have a reflected wave "-f(-x-vt)" (given that the incident wave is f(x-vt) ).
My question is probably really silly, but I can't understand why the reflected wave is "-f(-x-vt)" and not "-f(x+vt)" (travelling in the other direction, with inverted amplitude).
I hope I chose the right section since this is my first post here!
Thanks in advance to anyone who will reply to this (probably) really silly question!
I am currently studying traveling waves and reflection but I didn't understand a part of my last lesson.
If we consider a string with a loose end and the other end attached to a wall we expect the string to have zero displacement at the wall and to have a reflected wave "-f(-x-vt)" (given that the incident wave is f(x-vt) ).
My question is probably really silly, but I can't understand why the reflected wave is "-f(-x-vt)" and not "-f(x+vt)" (travelling in the other direction, with inverted amplitude).
I hope I chose the right section since this is my first post here!
Thanks in advance to anyone who will reply to this (probably) really silly question!