- #1
alpuy
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Hi all, i agree with you that those guys that use Oxyhydrogen to increase MPGs in their vehicles must be violating some physics laws but the aim of this post is to understand why.
Lets call:
Eq : Chemical Enegry
Ee : Electrical Energy
Emec : Mechanical Energy:
Ecal : Calorific Energy
I imagine an engine as a device that turns Eq stored in the fuel into Ee in the alternator, Emec for moving the car and and Ecal for heating the engine and thrown to the air in the exhaust.
So Eq = Ee + Emec +Ecal
When the guys use Oxyhydrogen the engine wastes more energy in electricity let's call it Ee1 and the mecanical energy is reduced by Ee1.
So Eq = Ee + Ee1 + Emec - Ee1 + Ecal
Emec2 = Emec - Ee1
Ee2 = Ee + Ee1
Eq = Ee2 + Emec2 + Ecal, Emec2 < Emec and Ee2 > Ee
k*Ee2 is the energy that the Oxyhydrogen has.
Eq + k*Ee2 = Ee2 + Emec3 + Ecal3
Can it happen that by adding the Oxyhydrogen Ecal3 is reduced more than the increase of Emec3?
Which laws is it violating?
Thank me for helping me understand this matter.
Regards
Lets call:
Eq : Chemical Enegry
Ee : Electrical Energy
Emec : Mechanical Energy:
Ecal : Calorific Energy
I imagine an engine as a device that turns Eq stored in the fuel into Ee in the alternator, Emec for moving the car and and Ecal for heating the engine and thrown to the air in the exhaust.
So Eq = Ee + Emec +Ecal
When the guys use Oxyhydrogen the engine wastes more energy in electricity let's call it Ee1 and the mecanical energy is reduced by Ee1.
So Eq = Ee + Ee1 + Emec - Ee1 + Ecal
Emec2 = Emec - Ee1
Ee2 = Ee + Ee1
Eq = Ee2 + Emec2 + Ecal, Emec2 < Emec and Ee2 > Ee
k*Ee2 is the energy that the Oxyhydrogen has.
Eq + k*Ee2 = Ee2 + Emec3 + Ecal3
Can it happen that by adding the Oxyhydrogen Ecal3 is reduced more than the increase of Emec3?
Which laws is it violating?
Thank me for helping me understand this matter.
Regards