Does Work in an Inclined System Only Occur in the Y Direction?

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Work is defined as the product of displacement in the direction of the force and the magnitude of the force applied. In an inclined system, work can occur in both the x and y directions, but it is important to consider the direction of the forces involved. The force pushing the block up the incline can be decomposed into x and y components, with only the component parallel to the displacement contributing to work. The confusion arises from the relationship between the force components and gravity; while gravity does influence work, the x component can also contribute depending on the angle of the incline. Ultimately, work is a scalar quantity that depends on the effective force acting in the direction of displacement.
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A block is pushed up an incline over a distance.

Now I have to find the work in the system, so my question is, does work only exist in the y direction? Is there work in the x direction of the force while pushing up the incline?
 
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What is work?

It is the product of the displacement along the direction of the force with the magnitude of the force applied

Vectorially work is (for constant force) F.s where [.] means dot product of the F vector and s vector

If F is not constant then W = integral of F.ds

Work is a scalar: So how can work exist in x-direction or y-direction?
 
I split the force pushing the block up the incline into two forces on the x-y coordinates, so Fx and Fy. I'm confused on whether Fx . d does any work since it is normal to the gravity. I assumed that the gravity is the only source that creates work for the F because Fy is acting parallel to the gravity, and so work is done, for the Fy component of F.
 
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