Underwater Pressure sunken ocean liner

AI Thread Summary
The discussion focuses on calculating the gauge pressure and depth of a sunken ocean liner, where the absolute pressure is 413 atmospheres and the surrounding saltwater density is 1025 kg/m^3. To find the gauge pressure, it is clarified that atmospheric pressure must be excluded, leading to the equation Pgauge = Pabsolute - Patmosphere. For depth calculation, the conversion from atmospheres to pascals is discussed, using the factor 1.013 x 10^5, followed by division by the product of density and gravitational acceleration. The calculations confirm that the approach taken is correct, affirming the accuracy of the work presented. The thread concludes with a consensus that the calculations are valid.
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Homework Statement


While exploring a sunken ocean liner, the principal research found the absolute pressure on the robot observation submarine at the level of the ship to be 413 atmospheres. The density of the surrounding saltwater was 1025kg/m^3. Calculate the gauge pressure on the sunken ocean liner. Calcuate the depth of the sunken ocean liner.


Homework Equations


Pabsolute = Pgauge + Patmosphere
P=Dgh


The Attempt at a Solution


For the gauge pressure, I know that atmospheric pressure is usually 1, but because we are underwater, isn't it a lot higher or is it the force that we feel that's high?
Is it just 413 - 1 = Pgauge?

Also for depth, I know you have to conver 412 atmospheres. Do you multiply it by 1.013x10^5 because that's the conversion factor with meters in it and then just divide by (1025 x -10) to get 4071.8m below the surface of the water?
 
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Indeed; a good idea is to convert things from atmospheres into N / m^2.

Though, you can combine these two equations =).

Gauge pressure excludes atmospheric pressure by the way.
 
No, I know that. That's why I subtracted one. My work is right though, yes?
 
velvetymoogle said:
No, I know that. That's why I subtracted one. My work is right though, yes?

All your work is fine. :smile:
 
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