Unexplained energy in nuclear process

LHarriger
Messages
68
Reaction score
0
I was talking to a guy the other day who said that back in 1954 he worked for the military on nuclear reactors (or something along those lines). He said that back then there were nuclear processes where all of the energy could not be accounted for. This missing or extra energy was very small and they used the symbol \zeta to represent it. Since then he has not been involved in physics and still doesn't know what this energy term was due to. I told him it was probably due to not including neutrinos in the processes but he said they took those into account. Does anyone know what this energy is from?
 
Physics news on Phys.org
Sorry, that's the wrong symbol. It wa xi, \xi that they used.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top