Uniform Boundedness of Derivative Sequence of C^1([a,b],R) Functions

johnson12
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Im having trouble showing that given a sequence of uniformly bounded C^1([a,b],R) functions,
the derivative sequence is uniformly bounded.
Any suggestions are helpfull
 
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If by 'uniformly bounded', you mean |f_n(x)|<M for some constant M, it's not true that the derivatives are necessarily bounded.
 
Youre right, the reason I ask is b/c I am trying to prove that every bounded sequence in C^1 has a convergent subsequence, Arzela Ascoli type problem.
 
What do you mean by a 'bounded sequence' in C^1? sin(n*x) is a bounded sequence in C^1 (in the sense |f_n|<=1). But it has no convergent subsequence. You need some sort of premise to get the equicontinuity from.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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