Uniform Circular Motion in a Watch

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eagles12
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Homework Statement



The second hand on a watch has a length of 4.5mm and makes one revolution in 60s. What is the speed of the end of the second hand as it moves in uniform circular motion?


Homework Equations



ac=v^2/r

The Attempt at a Solution



ac=v^2/4.5
 
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speed = distance/time
How far does the end of the hand move in 1 revolution?
How long does that take?
 
The equation you need to use here is:
v = ωr
Where ω is angular velocity.

The angular velocity is given by:
ω = Δθ / Δt

Thus the angular velocity of the second hand is known from the statement of your problem. Hope this helps.