Uniform Electric Field of a proton

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SUMMARY

A proton in a uniform electric field experiences constant acceleration in the direction of the field. This conclusion is based on the relationship defined by the equation E = m*a/q, where E represents the electric field, m is mass, a is acceleration, and q is charge. Since the proton is positively charged, it accelerates in the same direction as the electric field. Therefore, the correct answer to the homework question is option c: constant acceleration in the direction of the electric field.

PREREQUISITES
  • Understanding of electric fields and their properties
  • Familiarity with Newton's second law of motion
  • Knowledge of charge interactions in physics
  • Basic proficiency in vector mathematics
NEXT STEPS
  • Study the concept of electric field strength and its calculation
  • Learn about the motion of charged particles in electric fields
  • Explore the implications of uniform versus non-uniform electric fields
  • Investigate the role of force and acceleration in classical mechanics
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism, as well as educators seeking to clarify concepts related to electric fields and particle motion.

Soaring Crane
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Homework Statement



In a uniform electric field, a proton has a

a. constant velocity in the direction of the field.
b. constant velocity in the opposite direction of the electric field.
c. constant acceleration in the direction of the electric field.
d. constant acceleration in a direction opposite the electric field.
e. constant acceleration in a direction perpendicular to the electric


Homework Equations



Possibly vector E = m*a/q

The Attempt at a Solution



Is the correct answer c. constant acceleration in the direction of the electric field?

A uniform electric field has the same magnitude and direction throughout the region. Wouldn't the proton then have a constant acceleration, and the direction of the acceleration (also force?) would be in the field's same direction since the charge is positive?

Thanks.
 
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Correct. Good job.
 
Your logic seems to be correct.
 

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