Uniformly charged rod(exam in 3 hours, )

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A uniformly charged rod measuring 11.9 cm with a total charge of -17.7 μC is under examination for its electric field at a point 46.2418 cm from its center. The initial formula provided, E = KQ / (a(a + l)), is not yielding correct results, prompting discussions about the variables involved. Clarification is sought on whether 'a' represents the distance to the nearest point of the rod. An alternative approach suggests calculating the electric field using an integral, which may provide a more accurate result. The revised formula proposed for the electric field is E = KQ(l / (a^2 - (l^2 / 4))), assuming the calculation is made outside the rod.
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Homework Statement


A rod 11.9 cm long is uniformly charged and
has a total charge of −17.7 μC.
Find the magnitude of the electric field
along the axis of the rod at a point 46.2418 cm
from the center of the rod. The Coulomb con-
stant is 8.98755 × 109 N · m2/C2.

lecture problem I am trying to review for an exam in 3 hours.

our prof got this formula, but it isn't working for the numbers?

E = KQ / (a(a + l))

where K is columbs constant,
l = .119m
a = .462418m
Q = .0000177
 
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but it isn't working for the numbers?
What do you get, what do you expect?
Maybe a is the distance to the closest point of the rod in this formula?

You can calculate the electric field with an integral, this does not need any special formulas.

I did some quick calculation and got $$E=KQ\frac{l}{a^2-\frac{l^2}{4}}$$
up to constant prefactors, and with the assumption that the electric field is calculated outside the rod.
 
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