Uniformly Distribution Problem

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Homework Help Overview

The discussion revolves around a problem involving random variables drawn from uniform distributions. Specifically, it examines the joint probability density of two variables, X and Y, and seeks to determine probabilities related to their sums.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the probability of the sum of two random variables equaling 3 and whether this probability is zero due to the nature of a line in a continuous distribution. There are also attempts to calculate the probability of the sum being greater than 3, with some participants providing calculations and questioning the correctness of their results.

Discussion Status

The discussion is active, with participants sharing their calculations and seeking verification of their reasoning. There is an ongoing exploration of the implications of the uniform distribution on the probabilities being calculated.

Contextual Notes

Participants are working under the constraints of uniform distributions defined over specific intervals and are questioning the assumptions related to the area under the probability density function.

Askhwhelp
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A random variable X drawn from a uniform [0,3] distribution and a random variable y is independently drawn randomly drawn from a uniform [0,4] distribution. The joint probability density f(x,y) is also uniform, with support given by 0 ≤ x ≤ 3, 0 ≤ y ≤ 4. Find the probability for the sum of two randomly selected number is 3
This should be 0 because a line does not have any area, right?
Find the probability for the sum of two randomly selected number greater than 3
12-4.5 = 7.5/12 = .625, right?
 
Last edited:
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Askhwhelp said:
A random variable X drawn from a uniform [0,3] distribution and a random variable y is independently drawn randomly drawn from a uniform [0,4] distribution. The joint probability density f(x,y) is also uniform, with support given by 0 ≤ x ≤ 3, 0 ≤ y ≤ 4. Find the probability for the sum of two randomly selected number is 3
This should be 0 because a line does not have any area, right?
Find the probability for the sum of two randomly selected number greater than 3
12-4.5 = 7.5, right?

Show your work.
 
ray vickson said:
show your work.

3*4 - p(y<=3) = 12 - 3*3/2 = 12-4.5= 7.5/12 = .625
 
Last edited:
Please check it thx
 

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