MHB Unit Circle Problems solve cosW=sin20, sinW=cos(-10), sinW< 0.5 and 1<tanW

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To solve the unit circle problems, the angle W for cos(W) = sin(20) is determined to be 70 degrees, as cos(70) equals sin(20). For sin(W) = cos(-10), W is found to be 100 degrees, since sin(100) equals cos(-10). The condition sin(W) < 0.5 identifies angles in the first and fourth quadrants, specifically below 30 degrees and above 150 degrees. For 1 < tan(W), W must be in the second or fourth quadrants, specifically between 45 degrees and 225 degrees. Using graphs of y = sin(x) and y = tan(x) can aid in visualizing these relationships.
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Without a calculator, find all solutions w between 0 and 360, inclusive, providing diagrams that support your results.

1) cosW=sin20

2) sinW=cos(-10)

3) sinW< 0.5

4) 1<tanW
 
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You titled this "unit circle problems". Have you drawn a unit circle? Do you know that, at each (x, y) point on the circle, x= cos(\theta) and y= sin(\theta)? Where is sin(20) on that circle? So for what angle is cos(W)= sin(20)?
 
yes I am aware that y= sin(theta) and x= cos(theta)
and yes I drew my unit circle
so sin20 is in the first quadrant but I am not sure how to import images here, if possible
and cos70= sin 20, I figured that out a few days ago, however I am stuck on 3 and 4
 
Instead of using a unit circle, for 3 and 4, draw the graphs of y= sin(x) and y= tan(x). Compare the graph of y= sin(x) with the graph of y= 1/2 and compare the graph of y= tan(x) with y= 1. You should know that sin(x)= 1/2 for \pi/6 radians (30 degrees) and 5\pi/6 radians (150 degrees) and that tan(x)= 1 for \pi/4 radians (45 degrees) and 5\pi/4 radians (225 degrees). (There is a nice graphing app at https://www.desmos.com/calculator.)
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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