Unitary Transformation Problem

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SUMMARY

The discussion focuses on proving that a linear and norm-preserving operator T on a complex vector space V is unitary. Key definitions include linearity, norm-preserving transformations, and the properties of inner products in complex spaces. The user initially struggles with demonstrating equality of imaginary parts in the inner product but successfully resolves this by substituting x with ix, confirming that both real and imaginary parts of (T(x), T(y)) match (x, y). This establishes T as a unitary operator.

PREREQUISITES
  • Understanding of linear transformations in vector spaces
  • Familiarity with norm-preserving properties and inner products
  • Knowledge of complex numbers and their conjugates
  • Proficiency in calculus, particularly as presented in Tom M Apostol's second calculus book
NEXT STEPS
  • Study the properties of unitary operators in linear algebra
  • Explore the implications of norm-preserving transformations in functional analysis
  • Learn about the role of complex conjugates in inner product spaces
  • Review advanced topics in vector spaces, focusing on linearity and transformations
USEFUL FOR

Students of mathematics, particularly those studying linear algebra and functional analysis, as well as educators seeking to deepen their understanding of unitary transformations and their properties.

Sam_Goldberg
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Homework Statement



Hi guys, I'm working on a question in Tom M Apostol's second calculus book, on page 141, number 5. It is: Prove that if T (an operator on a vector space V) is linear and norm-preserving, then T is unitary.

Homework Equations



Okay, a transformation T is linear if it satisfies (x and y are vectors, c is a complex scalar):

T(x + y) = T(x) + T(y)
T(cx) = cT(x)

A norm-preserving transformation satisfies for all x (these are norms and inner products):

|T(x)| = |x|
Equivalently, (T(x), T(x)) = (x, x)

Finally, T is unitary if for all x and y:

(T(x), T(y)) = (x, y)

Note that this is a complex vector space, so, in particular:

(x , y) = (y, x)*

where * is the complex conjugate. This fact is the key to my difficulties in this problem.

The Attempt at a Solution



Here goes:

(T(x), T(y))
= (T(x + y), T(y)) - (T(y), T(y))
= (T(x + y), T(y)) - (y , y)
= (T(x + y), T(x + y)) - (T(x), T(x)) - (T(y), T(x)) - (y, y)
= (x + y, x + y) - (x, x) - (y, y) - (T(y), T(x))
= (x, y) + (y, x) - (T(y), T(x))

Therefore: (T(x), T(y)) + (T(y), T(x)) = (x, y) + (y, x)

Now, due to the complex conjugate rule for the inner product, I can only deduce from this equation that:

(T(x), T(y)) + (T(x), T(y))* = (x, y) + (x, y)*

So, I have only proven that the real parts of (T(x), T(y)) and (x, y) are equal, not the imaginary parts. I would appreciate any inputs on how to prove this too. Thanks.
 
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Try it again with the inner product (T(x), T(iy)), or some other combination with an i in there.
 
g_edgar said:
Try it again with the inner product (T(x), T(iy)), or some other combination with an i in there.

You are absolutely right. If we replace in my final equation x by ix, we get:

i(T(x), T(y)) - i(T(x), T(y))* = i(x, y) - i(x, y)*

which clearly shows that the imaginary parts of (T(x), T(y)) and (x, y) are equal. Thank you very much.
 

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