Myslius said:
When we talk about acceleration, we mean how velocity changes over time. If velocity over time increases - it means object is accelerating.
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No, that is not what we mean by acceleration in cosmology. There is no definite velocity that characterizes the expansion. We are not talking about the change over time of some velocity.
I'll try to explain how the term is used.
First learn the idea of the Hubble rate, which is a percentage growth rate of distance (measured in the universal rest frame, in which distances grow but galaxies mostly don't move save for small random motions).
The Hubble rate has been decreasing since very early days and is expected to continue to decline, but less rapidly. It is currently about 1/140 of one percent every million years. That is on average largescale distances (between objects at rest) increase by about 1/140 of a percent every million years.
There are online calculators which can tell you, for a given redshift, what the Hubble rate was back then when the distant galaxy emitted the light that now has that redshift, that we see it with.
Then learn about the
scale factor a(t) a function of time. By convention a(present)=1.
It turns out that the Hubble rate is equal to a'(t)/a(t). That is the ratio of the derivative or slope of the scalefactor to the scalefactor itself. A fractional increase per unit time. You can express a'(t)/a(t) as a percentage growth of distance per unit time.
a(t) is not a velocity. a'(t) is not a velocity. the Hubble rate is not a velocity (it is a percentage growth rate of distances between stationary objects.)
a(t) and the Hubble rate are governed by an equation or more exactly by a pair of equations. They are simple equations but out of laziness I nearly always use the readymade online calculators that solve them for you automatically.
What is meant in cosmology by the acceleration or "speeding up" of expansion is that the
second derivative a"(t) of the scalefactor a(t) is positive.
Not only is the a(t) increasing with time but the
slope of the a(t) curve is increasing.
Do you understand how a'(t) can be increasing and yet the Hubble rate a'(t)/a(t) can be decreasing?
It sometimes helps to think of money in the bank---say in a savings account where the bank is very gradually decreasing the percentage of interest that they pay to savers. But the total dollars in your account nevertheless keeps going up by a greater and greater amount each year. Because the bank is easing off the interest rate only very slowly.
I don't believe that thinking in terms of conventional motion or velocity will help you understand this. Distance change is convenient to think about as a change in *geometry*, not motion as we know it. Everybody's distances increase and nobody gets anywhere by it. Relative positions don't change (except for small individual random motions whose effect on the big picture is negligible).